[TIP] [통계,사회,심리,행정,경영] 확률의 입문_7번째 판 [solution]입니다.
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다. 7. (a) 6! = 720
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26 ⋅ 26 ⋅ 10 ⋅ 10 ⋅ 10 ⋅ 10 ⋅ 10 = 67,600,000
sack j of wife i is the mother of the kitten; and l represents the number of the kitten of cat k in
(c) 4!3! = 144
5. There were 8 ⋅ 2 ⋅ 9 = 144 possible codes. There were 1 ⋅ 2 ⋅ 9 = 18 that started with a 4.
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Chapter 1
2. 64 = 1296
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sack j of wife i. By the generalized principle there are thus 7 ⋅ 7 ⋅ 7 ⋅ 7 = 2401 kittens
that order, we see by the generalized basic principle that there are 2 ⋅ 1 ⋅ 2 ⋅ 1 = 4 possibilities.
numbers from 1 to 7. The number i represents which wife is carrying the kitten, j then
(b) 2 ⋅ 3! ⋅ 3! = 72
6. Each kitten can be identified by a code number i, j, k, l where each of i, j, k, l is any of the
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represents which of that wife’s 7 sacks contain the kitten; k represents which of the 7 cats in
1. (a) By the generalized basic principle of counting there are
(b) 26 ⋅ 25 ⋅ 10 ⋅ 9 ⋅ 8 ⋅ 7 ⋅ 6 = 19,656,000
레포트 > 자연과학계열
numbers 1, …, 20 and so there are 20! different possible assignments.
(d) 6 ⋅ 3 ⋅ 2 ⋅ 2 ⋅ 1 ⋅ 1 = 72
only one person can be assigned to a job, it follows that the sequence is a permutation of the
4. There are 4! possible arrangements. By assigning instruments to Jay, Jack, John and Jim, in
Problems
3. An assignment is a sequence i1, …, i20 where ij is the job to which person j is assigned. Since
솔루션, 확률의 입문 7판, 7판, 확률의 입문
[통계,사회,심리,행정,경영] 확률의 입문_7번째 판 [solution]입니다.
